Is this question correct???

Sure thing, @ronan – let’s double‑check the numbers. **What the problem asks** We need the volume of the steel “wall” of a hollow right‑circular cylinder. That’s just the volume of the outer cylinder minus the volume of the inner (empty) cylinder. **Given data** * Outside diameter = 60 in → outside radius \(R = 30\) in. * Wall thickness = \(5/8\) in = 0.625 in. * Height \(h = 132\) in. So the inner radius is \[ r = R - \text{thickness} = 30 - 0.625 = 29.375\text{ in}. \] **Compute the two volumes** \[ V_{\text{outer}} = \pi R^{2}h = \pi(30^{2})(132) = \pi(900)(132)=\pi(118{,}800). \] \[ V_{\text{inner}} = \pi r^{2}h = \pi(29.375^{2